a 12% return on an amount x invested is
10000 invested at 10% is 11000
I would try
1.) An investor wishes to realize a return of 12% on a total of two investments. If he has $10,000 invested at 10%, how much additional money should be invested at 16%?
2.) A woman invested $25000 in two business ventures. Last year she made a profit of 15% from the first venture but lost 5% from the second venture. If last year's income from the two investments was equivalent to a return of 8% on the entire amount invested, how much had she invested in each venture?
Can you show me how it's done? I have the answers, I just don't know how to solve it. Thanks!
Ok, I see that my equations are the same. Thanks guys.
So, in summary:
.10(10000) + .16x = .12(10000 + x)
1000 + .16x = 1200 + .12x
.16x-.12x = 1200 - 1000
.04x = 200
x = 5000
.15x - .05(25000 - x) = .08(25000)
.15x - 1250 + .05x = 2000
.2x = 3250
x = 16250
Are those right?