i have r = [1 - ( 1 - 1/Tr)^L ] x 100% and i need Tr and i have L = 2 and r = 2%
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Originally Posted by question i have r = [1 - ( 1 - 1/Tr)^L ] x 100% and i need Tr and i have L = 2 and r = 2% If your expression is correct we have 2=(1-(1-1/Tr)^2)*100 so: 0.02=1-(1-1/Tr)^2 bringing the 1 over to the left: 0.02-1=-(1-1/Tr)^2 or: 0.98=(1-1/Tr)^2 so: 1-1/Tr=sqrt(0.98) ~= 0.98995 so 1/Tr~=1- 0.98995=0.01005 Tr~=99.5~=100 RonL
Last edited by CaptainBlack; January 13th 2007 at 11:18 AM. Reason: add more precission to the calculation
Originally Posted by question i have r = [1 - ( 1 - 1/Tr)^L ] x 100% and i need Tr and i have L = 2 and r = 2% (Just a note: I seem to recall doing this before and doing something silly with a "log" term at this point. I don't know why I did it that way, and it may well have been wrong. My apologies if I'm remembering that correctly!) With r = 2 and L = 2: -Dan
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