1. ## Common Factor

Factor out the common factor of 2x from

14x^(3/5) * 16x^(1/2)

2. Originally Posted by sharkman
Factor out the common factor of 2x from

14x^(3/5) * 16x^(1/2)
The first step will be to multiply the two factors:

$14x^{\frac{3}{5}}\, \times\, 16x^{\frac{1}{2}}\, =\, 14\times 16\times x^{\frac{3}{5}\, +\, \frac{1}{2}}\, =\, 224x^{\frac{11}{10}}$

You can then factor out 224x (or just the specified 2x), leaving behind one tenth-root of x, times whatever you didn't factor out.

This seems a very odd exercise....

3. Originally Posted by stapel
The first step will be to multiply the two factors:

$14x^{\frac{3}{5}}\, \times\, 16x^{\frac{1}{2}}\, =\, 14\times 16\times x^{\frac{3}{5}\, +\, \frac{1}{2}}\, =\, 224x^{\frac{11}{10}}$

You can then factor out 224x (or just the specified 2x), leaving behind one tenth-root of x, times whatever you didn't factor out.

This seems a very odd exercise....
I agree. I looked at it before, but was reluctant to reply because I could see absolutely no reason to factor out a 2x....perhaps the OP copied the question incorrectly.

4. ## Thanks...

Thank you your input and information. I will review your replies and practice similar questions.