ln(x-2)+ln(2x-3)=2lnx

solve for x. My brain must have gone to sleep, i have the answer but can't understand why i can't use:

e^ln(x-2) + e^ln(2x-3) = e^lnx^2

(x-2) + (2x-3) = x^^2

and then solve quadratic

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- Aug 28th 2009, 07:47 AMattwoodpsolve logarithmic equation
ln(x-2)+ln(2x-3)=2lnx

solve for x. My brain must have gone to sleep, i have the answer but can't understand why i can't use:

e^ln(x-2) + e^ln(2x-3) = e^lnx^2

(x-2) + (2x-3) = x^^2

and then solve quadratic - Aug 28th 2009, 07:57 AMynj
- Aug 28th 2009, 09:38 AMDefunkt
- Aug 28th 2009, 11:45 AMstapel
Use

**log rules**to convert the equation to:

Then equate the arguments, and solve the resulting quadratic equation. (Wink)