How do i prove this? If one root of the equation ax^2 + bx + c = 0 is square of the other, show that b^3 + a^2.c + a.c^2 = 3abc
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If x,y are roots and one is the square of the other, then or . It follows that Now Viete's formulas say and . So from which by multipliyng by the conclusion follows.
Originally Posted by saberteeth How do i prove this? If one root of the equation ax^2 + bx + c = 0 is square of the other, show that b^3 + a^2.c + a.c^2 = 3abc Or
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