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Thread: algebra help please!

  1. January 12th 2007, 11:15 PM #1
    u.........
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    algebra help please!

    Im really stuck right now

    evaluate x^2-x for the value of x satisfying

    4(x-2)+2=4x-x(2-x)
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  2. January 12th 2007, 11:36 PM #2
    earboth
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    Quote Originally Posted by urlostaznbro View Post
    Im really stuck right now

    evaluate x^2-x for the value of x satisfying

    4(x-2)+2=4x-x(2-x)
    Hello,

    first solve the equation for x:

    4(x-2)+2=4x-x(2-x) \Longleftrightarrow 4x-8+2=4x-2x+x^2 which simplifies to:

    x^2-2x+6=0\ \Longrightarrow \ x_1=1+2i\ \vee \ x_2=1-2i

    Now plug in these values into the given term:

    (1+2i)^2-(1+2i)=1+4i-4-1-2i=-2+2i

    (1-2i)^2-(1-2i)=1-4i-4-1+2i=-4-2i

    EB
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