I don't completely understand this.

multiply and simplify

36y^2*3y-12

3y^2-24y+48 6y

here is what I understand

(36y^2)(3y-12)

(3y^2-24y+48)(6y)

(36y^2)3(y-4)

3(y^2-8y+16)(6y)

what do I do next if I am correct?

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- Aug 27th 2009, 11:32 AM #1

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- Aug 27th 2009, 11:43 AM #2

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You are correct so far.

Well, we can see we can cross-out the 3 on top and bottom to get

$\displaystyle \frac{(36y^2)(y-4)}{(y^2-8y+16)(6y)}$

Let's try to cross-out the 6y on the bottom:

$\displaystyle \frac{(6y)(6y)(y-4)}{(y^2-8y+16)(6y)}$

$\displaystyle \frac{(6y)(y-4)}{(y^2-8y+16)}$

We can factor y^2-8y+16 to get (y-4)^2

$\displaystyle \frac{(6y)(y-4)}{(y-4)^2}$

We can cross out the (y-4) on the bottom and top

$\displaystyle \frac{6y}{y-4}$

And that's as far as we can go.

- Aug 27th 2009, 11:49 AM #3

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