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Math Help - Ah, just crack my minds...weird, finding quadratic equations

  1. #1
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    Wink Ah, just crack my minds...weird, finding quadratic equations

    Hai, everyone..nice to meet u all and thanks 4 all those had put efforts to answer my question...okay, this one I find it accidentally and I'm quite curious about it, do anyone(s) can help me out?? Thanks...

    1) Form a quadratic equation with roots which exceed by 2 the roots of the quadratic equation 3x^2 - (p - 4)x - (2p + 1) = 0.
    Find the values of p for which the given equation has equal roots.

    I'm just manage to find until half of the solutions and don't know how to find p??..Could someone help me...
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  2. #2
    Senior Member nikhil's Avatar
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    since roots are equal therfor discriminant =0 hence
    (p-4)^2+12(2p+1)=0
    solve it and obtian the value of p
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