please i need help with the processes of these two simultaneous equations!!:
7x + 2y = -4
3x + 4y = 14
and...
x/2 + y/3 = 5
x/3 + y/4 = 1
$\displaystyle 7x + 2y = -4$ ...(1)
$\displaystyle 3x + 4y = 14$ ...(2)
Working with (1)
$\displaystyle 7x + 2y = -4$
$\displaystyle 2y = -4-7x$
$\displaystyle y = \frac{-4}{2}-\frac{7x}{2}$
Now sub this into (2)
$\displaystyle 3x + 4y = 14$
$\displaystyle 3x + 4 \left(\frac{-4}{2}-\frac{7x}{2}\right)= 14$
Can you find x now?
Use the same process as in my first post.
$\displaystyle \frac{x}{2} + \frac{y}{3} = 5$ ...(1)
$\displaystyle \frac{x}{3} + \frac{y}{4} = 1$ ...(2)
Working on (1)
$\displaystyle \frac{x}{2} + \frac{y}{3} = 5$
$\displaystyle \frac{y}{3} = 5 - \frac{x}{2}$
$\displaystyle y = 15 - \frac{3x}{2}$
Now into (2)
$\displaystyle \frac{x}{3} + \frac{15 - \frac{3x}{2}}{4} = 1$
You can take it from here....
Once you have a solution for x substittue this into either (1) or (2) to find y.