# Word Problem for Algebra.

Show 40 post(s) from this thread on one page
Page 1 of 2 12 Last
• Aug 24th 2009, 07:51 PM
BrilliantLegacy
Word Problem for Algebra.
Shawn Hetrick has an annual interest income of \$3290 from two investments. He has \$7000 more invested at 8% than he has invested at 6%. find the amount invested at each rate.
Can anyone solve this for me? I'm a bit confused.. Well not really, more like I'm stuck. The problem I have is that this question doesn't give to total he invested on the 8% and 6%. I just can't think of an equation for this. (Doh)(Wait)
• Aug 24th 2009, 08:05 PM
saar4ever
one equation could be
x=amount invested in 8%
y=amount invested in 6%
$0.08x+0.06y=3290$
find the other equation then use elimination method to eliminate x and find y then use one of the equations to plug in y and find x
other equation is something like
$x+7000=y$
which equals to:
$x-y=7000$
then just use simple elimination and u shall find the answer
• Aug 24th 2009, 08:12 PM
11rdc11
$.08(x+7000) + .0 6(x) = 3290$
• Aug 24th 2009, 08:20 PM
saar4ever
Quote:

Originally Posted by 11rdc11
$.8(x+7000) + .6(x) = 3290$

0.8 is 80% while 0.08 is 8%
so you were wrong the the right equation is still
$

0.08x+0.06y=3290
$

and
$

x-y=7000
$

now just use those 2 to solve it with elimination
• Aug 24th 2009, 08:34 PM
11rdc11
Quote:

Originally Posted by saar4ever
0.8 is 80% while 0.08 is 8%
so you were wrong the the right equation is still
$

0.08x+0.06y=3290
$

and
$

x-y=7000
$

now just use those 2 to solve it with elimination

Thanks for spotting that. I used the equation I did incase he or she does not know how to work with 2 variables
• Aug 24th 2009, 08:40 PM
BrilliantLegacy
Sweet, thanks guys! I can see the picture of it (Wait) I still need more practice.
The thing is that I have is making an equation out of a word problem (Crying)
• Aug 24th 2009, 08:43 PM
BrilliantLegacy
A freight train travels 60 miles in the same time that a passenger train travels 100miles. If the passenger train goes 30miles per hour faster than the freight train, find the rate of each.

Honestly, I don't have an idea of what this question is trying to ask. (Thinking)
• Aug 24th 2009, 08:46 PM
BrilliantLegacy
Quote:

Originally Posted by saar4ever
0.8 is 80% while 0.08 is 8%
so you were wrong the the right equation is still
$

0.08x+0.06y=3290
$

and
$

x-y=7000
$

now just use those 2 to solve it with elimination

Don't solve it for me but can you give me a brief explain of x and y using in an equation? I'm only use to working with x (Shake) Yet, I'm in a community college learning algebra.
Sorry for the trouble and thanks for helping me out, I'm still a newb.
• Aug 24th 2009, 08:56 PM
saar4ever
multiply this by 100
$

0.08x+0.06y=3290
$

=
$

8x+6y=329000
$

then divide by 6 and add equation 1 and 2
then u have x all alone and divide it to find what it is
then plug in x into the second equation to find out what y is
• Aug 24th 2009, 09:00 PM
saar4ever
Quote:

Originally Posted by BrilliantLegacy
A freight train travels 60 miles in the same time that a passenger train travels 100miles. If the passenger train goes 30miles per hour faster than the freight train, find the rate of each.

Honestly, I don't have an idea of what this question is trying to ask. (Thinking)

60x=100y
x=y+30

then

60x-100y=0
x-y=30

then

-0.6x+y=0
x-y=30

0.4x=30

x=75mph
y=45mph
just double checked pretty sure its right answer
hope it makes sense
• Aug 24th 2009, 09:09 PM
BrilliantLegacy
Quote:

Originally Posted by saar4ever
60x=100y
x=y+30

then

60x-100y=0
x-y=30

then

-0.6x+y=0
x-y=30

0.4x=30

x=75mph
y=45mph
just double checked pretty sure its right answer
hope it makes sense

Thanks a lot dude. I have a pre-test tomorrow and you have just saved me!
• Aug 24th 2009, 09:09 PM
saar4ever
see ya
gl on the test hope u ace it
• Aug 24th 2009, 09:22 PM
BrilliantLegacy
Quote:

Originally Posted by saar4ever
see ya
gl on the test hope u ace it

Do you mind telling me the the answer for the first one? I want to make sure I have it right.
• Aug 24th 2009, 09:29 PM
11rdc11
Quote:

Originally Posted by saar4ever
60x=100y
x=y+30

then

60x-100y=0
x-y=30

then

-0.6x+y=0
x-y=30

0.4x=30

x=75mph
y=45mph
just double checked pretty sure its right answer
hope it makes sense

I got a different answer. Speeds are 75 and 105. The passenger should be faster

x=y-30 or x+30=y
• Aug 24th 2009, 09:32 PM
saar4ever
Quote:

Originally Posted by 11rdc11
I got a different answer. Speeds are 75 and 105. The passenger should be faster

x=y-30 or x+30=y

could be need to check it again
Show 40 post(s) from this thread on one page
Page 1 of 2 12 Last