What is the standard equation of the circle whose center is (-5,-4) and whose radius is 3? (x + 5)^2 + (y + 4) = 9
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Originally Posted by bobbyboy1111 What is the standard equation of the circle whose center is (-5,-4) and whose radius is 3? (x + 5)^2 + (y + 4) = 9 It is actually $\displaystyle (x + 5)^2 + (y + 4)^2 = 9$ The vector linking the center C (-5,-4) to any point M(x,y) has coordinates (x-(-5),y-(-4)) or (x+5,y+4) The distance between M and C is $\displaystyle \sqrt{(x + 5)^2 + (y + 4)^2}$
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