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Math Help - Why is my standard equation incorrect?

  1. #1
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    Why is my standard equation incorrect?

    What is the standard equation of the circle whose center is (-5,-4) and whose radius is 3?


    (x + 5)^2 + (y + 4) = 9
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  2. #2
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    Quote Originally Posted by bobbyboy1111 View Post
    What is the standard equation of the circle whose center is (-5,-4) and whose radius is 3?


    (x + 5)^2 + (y + 4) = 9
    It is actually (x + 5)^2 + (y + 4)^2 = 9

    The vector linking the center C (-5,-4) to any point M(x,y) has coordinates (x-(-5),y-(-4)) or (x+5,y+4)

    The distance between M and C is \sqrt{(x + 5)^2 + (y + 4)^2}
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