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Math Help - simplify

  1. #1
    Junior Member
    Joined
    Jun 2008
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    simplify

    Simplify the following expression:

    \frac{6v^2+6u^2+12uv}{3vx+3ux+4uw+4vw}


    there are four alphabets used, which are v, u ,x and w.

    what i tried to do is

    \frac{6v^2+6u^2+12uv}{3vx+3ux+4uw+4vw}
    = \frac{6v^2+6u(u+2v)}{(3x+4w)(v+u)}

    then...stuck...
    i think it can be further simplified..........

    any help is much appreciated....
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  2. #2
    MHF Contributor
    Joined
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    West Malaysia
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    Quote Originally Posted by wintersoltice View Post
    Simplify the following expression:

    \frac{6v^2+6u^2+12uv}{3vx+3ux+4uw+4vw}

    what i tried to do is

    \frac{6v^2+6u^2+12uv}{3vx+3ux+4uw+4vw}
    = \frac{6v^2+6u(u+2v)}{(3x+4w)(v+u)}

    then...stuck...
    i think it can be further simplified..........

    any help is much appreciated....
    \frac{6(v^2+2uv+u^2)}{(3vx+3ux)+(4uw+4vw)}

    \frac{6(v+u)^2}{3x(v+u)+4w(v+u)}

    \frac{6(v+u)^2}{(3x+4w)(v+u)}

    do u know what to do now ?
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  3. #3
    Junior Member
    Joined
    Jun 2008
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    Quote Originally Posted by mathaddict View Post
    \frac{6(v^2+2uv+u^2)}{(3vx+3ux)+(4uw+4vw)}

    \frac{6(v+u)^2}{3x(v+u)+4w(v+u)}

    \frac{6(v+u)^2}{(3x+4w)(v+u)}

    do u know what to do now ?
    i see....
    so the final answer is

    \frac{6(v+u)}{(3x+4w)}...

    thanks
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