eccentricity = sqrt(a^2 - b^2)/a (I think this formula is correct for the following ellipse) THANKS WILL BE GIVEN TO THOSE WHO HELP! [(x^2) / 25] +[(y-3)^2 / 9] = 1 e = SQRT(25^2 - 9^2)/25 e = SQRT( 625 - 81)/25 e = 23.32/ 25 e = .9328 Thanks
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Originally Posted by bobbyboy1111 eccentricity = sqrt(a^2 - b^2)/a (I think this formula is correct for the following ellipse) THANKS WILL BE GIVEN TO THOSE WHO HELP! [(x^2) / 25] +[(y-3)^2 / 9] = 1 e = SQRT(25^2 - 9^2)/25 e = SQRT( 625 - 81)/25 e = 23.32/ 25 e = .9328 No, you have squared the numbers twice. If the equation is then a=5, b=3 and , so e=4/5.
Last edited by Opalg; Aug 22nd 2009 at 11:54 PM.
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