i have log_L (1-r)
with L = 2 and r = 0.02
does any1 know how to put log to the base into a calculator or any other way of calculating it?
You appear to have $\displaystyle log_{2}(1-0.02)=log_{2}(0.98)$
When entering into a calculator, use the change of base formula.
$\displaystyle log_{b}(u)=\frac{log_{a}(u)}{log_{a}(b)}$
In this case, $\displaystyle \frac{log(0.98)}{log(2)}\approx{-0.02914}$
Do not confuse the change of base formula with the quotient rule for logs.