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Math Help - urgent help needed

  1. #1
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    urgent help needed

    can anyone help with this

    i have r = [ 1 - (1 - 1/Tr)^L]

    and i need to make Tr the subject urgently if someone could show me that would be great
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by question View Post
    can anyone help with this

    i have r = [ 1 - (1 - 1/Tr)^L]

    and i need to make Tr the subject urgently if someone could show me that would be great
    r = 1 - (1 - 1/Tr)^L

    r - 1 = - (1 - 1/Tr)^L

    1 - r = (1 - 1/Tr)^L

    log_L (1 - r) = 1 - 1/Tr

    1/Tr = 1 - log_L (1 - r)

    Tr = \frac{1}{1 - log_L (1 - r)}

    -Dan
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  3. #3
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    need help

    thanks the log to the base L also confuses me how exactly does it go into the calculator or is there another way of calculating it
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  4. #4
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    Quote Originally Posted by topsquark View Post
    r = 1 - (1 - 1/Tr)^L

    r - 1 = - (1 - 1/Tr)^L

    1 - r = (1 - 1/Tr)^L

    log_L (1 - r) = 1 - 1/Tr

    1/Tr = 1 - log_L (1 - r)

    Tr = \frac{1}{1 - log_L (1 - r)}

    -Dan
    does anyone know how to put the base log into a calculator or any other way of doing it?????
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