can anyone help with this i have r = [ 1 - (1 - 1/Tr)^L] and i need to make Tr the subject urgently if someone could show me that would be great
Follow Math Help Forum on Facebook and Google+
Originally Posted by question can anyone help with this i have r = [ 1 - (1 - 1/Tr)^L] and i need to make Tr the subject urgently if someone could show me that would be great $\displaystyle r = 1 - (1 - 1/Tr)^L $ $\displaystyle r - 1 = - (1 - 1/Tr)^L $ $\displaystyle 1 - r = (1 - 1/Tr)^L $ $\displaystyle log_L (1 - r) = 1 - 1/Tr$ $\displaystyle 1/Tr = 1 - log_L (1 - r)$ $\displaystyle Tr = \frac{1}{1 - log_L (1 - r)}$ -Dan
thanks the log to the base L also confuses me how exactly does it go into the calculator or is there another way of calculating it
Originally Posted by topsquark $\displaystyle r = 1 - (1 - 1/Tr)^L $ $\displaystyle r - 1 = - (1 - 1/Tr)^L $ $\displaystyle 1 - r = (1 - 1/Tr)^L $ $\displaystyle log_L (1 - r) = 1 - 1/Tr$ $\displaystyle 1/Tr = 1 - log_L (1 - r)$ $\displaystyle Tr = \frac{1}{1 - log_L (1 - r)}$ -Dan does anyone know how to put the base log into a calculator or any other way of doing it?????
View Tag Cloud