hi Brama Bull
f(x)=x^2-5x+5
for y intercept put x=0
so ew get
f(x)=0-0+5
hence y intercept is at y=5
now for x intercept put f(x)=0 so
x^2-5x+5=0
x=(5+-sqrt[5])/2
hence there are two x intercepts
one at x=(5+sqrt[5])/2 other at x=(5-sqrt[5])/2
Find the x, and y, intercepts for
f(x)= x^2-5x +5
I have the y intercept as (0,5)
the x intercept is where I am having a problem
-(-5)+or- sqrt of -5^2-4(1)(5) / 2(1)
then I calculated that into
5 + or - the sqrt of 25 +40/2
then I calculated that into
5 + or - sqrt of 45/2
That is were I get stuck, am I on the right path so far? if not please tell me where I have gone wrong?
Thanks.