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Math Help - Finding Intercepts

  1. #1
    Newbie
    Joined
    Aug 2009
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    20

    Finding Intercepts

    Find the x, and y, intercepts for
    f(x)= x^2-5x +5
    I have the y intercept as (0,5)
    the x intercept is where I am having a problem
    -(-5)+or- sqrt of -5^2-4(1)(5) / 2(1)
    then I calculated that into
    5 + or - the sqrt of 25 +40/2
    then I calculated that into
    5 + or - sqrt of 45/2

    That is were I get stuck, am I on the right path so far? if not please tell me where I have gone wrong?
    Thanks.
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  2. #2
    Senior Member nikhil's Avatar
    Joined
    Jun 2008
    Posts
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    hi Brama Bull
    f(x)=x^2-5x+5
    for y intercept put x=0
    so ew get
    f(x)=0-0+5
    hence y intercept is at y=5
    now for x intercept put f(x)=0 so
    x^2-5x+5=0
    x=(5+-sqrt[5])/2
    hence there are two x intercepts
    one at x=(5+sqrt[5])/2 other at x=(5-sqrt[5])/2
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