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Thread: Log help.

  1. #1
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    Log help.

    $\displaystyle \log_{8}x^{\frac{3}{2}} - \log_{8}x^{\frac{1}{2}} $


    Can some one please tell me how i work this out.
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  2. #2
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    Quote Originally Posted by el123 View Post
    $\displaystyle \log_{8}x^{\frac{3}{2}} - \log_{8}x^{\frac{1}{2}} $


    Can some one please tell me how i work this out.
    $\displaystyle \log(a) - \log(b) = \log\left(\frac{a}{b}\right)$
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  3. #3
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    thanks , what if the question says , that the equation equals 2.


    and gives me multiples answers to choose what x is. The answer is 64......i dont know why. Could you explain to me the process i go through to get that answer.
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  4. #4
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    Quote Originally Posted by el123 View Post
    thanks , what if the question says , that the equation equals 2.


    and gives me multiples answers to choose what x is. The answer is 64......i dont know why. Could you explain to me the process i go through to get that answer.
    $\displaystyle \log_8{x^{\frac{3}{2}}} - \log_8{x^{\frac{1}{2}}} = 2$

    $\displaystyle \log_8\left(\frac{x^{\frac{3}{2}}}{x^{\frac{1}{2}} }\right) = 2$

    $\displaystyle \log_8{x} = 2$

    change to an exponential equation ...

    $\displaystyle 8^2 = x$

    $\displaystyle 64 = x$

    in future, please post the entire question from the start.
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