# solving an application

• Jan 11th 2007, 03:04 AM
Patience
solving an application
A school had 900 students at the start of a school year. If there is an enrollment increase of 7% by the beginning of the next year, what is the
new enrollment?

Here is how I came up with the answer: (It just don't seem right)

900/B = 7/100 = 7*b = 900*100

7B = 90,000

B = 90,000/7 = 12,857 therefore the new enrollment is 12,857
• Jan 11th 2007, 03:10 AM
earboth
Quote:

Originally Posted by Patience
A school had 900 students at the start of a school year. If there is an enrollment increase of 7% by the beginning of the next year, what is the
new enrollment?

Here is how I came up with the answer: (It just don't seem right)
900/B = 7/100 = 7*b = 900*100
7B = 90,000
B = 90,000/7 = 12,857 therefore the new enrollment is 12,857

Hello,

an increase of 7% means that the 100% will be 107%. Now you can set up the proportion:

$\frac{900}{100}=\frac{N}{107}$ where N is the new number of students.
Solve for N. I've got 963 students

EB