1. ## Problem solving?

Kim placed an order for 98 gizmos which cost $445. A package of 7 gizmos cost$30, and a package of 5 gizmos cost $25. How many packages of each type did Kim order? Really not sure how to start it from there.. and how to put it into equations. 2. Hi fvaras89 Let : x = package of 7 gizmos y = package of 5 gizmos 1. If Kim buys one x and one y, she will get 12 gizmos -----> 7*1 + 5*1 = 12 If Kim buys two x and one y, she will get 19 gizmos -----> 7*2 + 5*1 = 19 If Kim buys three x and two y, she will get 31 gizmos -----> 7*3 + 5*2 = 31 If Kim has to buy 98 gizmos, can you find the equation ? ----> 1st equation 2. If Kim buys one x and one y, she will spend$55 -----> 30*1 + 25*1 = 55
If Kim buys two x and one y, she will spend $85 -----> 30*2 + 25*1 = 85 If Kim buys three x and four y, she will spend$190 -----> 30*3 + 25*4 = 190

If Kim has $445, can you find the equation ? -------> 2nd equation 3. Originally Posted by fvaras89 Kim placed an order for 98 gizmos which cost$445. A package of 7 gizmos cost $30, and a package of 5 gizmos cost$25. How many packages of each type did Kim order?

Really not sure how to start it from there.. and how to put it into equations.
Let x be the number of 7 gizmo packets and y be the number of 5 gizmo packets bought. Then:

7x + 5y = 98 .... (1)

30x + 25y = 445 .... (2)

Solve simultaneously.

4. Okay thanks, i solved them simultaneously and i got

7x + 5y = 98 (1)
30x + 25y = 445 (2)

(1) * 5

35x + 25y = 490 (3)

(3) - (2)

5x = 45
x = 9

then substitute into (1)

7(9) + 5y = 98
63 + 5y = 98
5y = 35
y = 7

Is that correct?

5. Originally Posted by fvaras89
Okay thanks, i solved them simultaneously and i got

7x + 5y = 98 (1)
30x + 25y = 445 (2)

(1) * 5

35x + 25y = 490 (3)

(3) - (2)

5x = 45
x = 9

then substitute into (1)

7(9) + 5y = 98
63 + 5y = 98
5y = 35
y = 7

Is that correct?
Does your solution work when you substitute it into the two equations? Check that and then you'll know.

6. oh yes it does!!! thanks heaps to you both