I have been sitting in my room for... 5 hours now, 5 hours!! Trying to do this algebra 2 sheet on quadratic equations and I am completley lost!!!
I can do the easy one's like
(t^2-9)=0
(t-3)(t+3)=0
t-3=0 t+3=0
t=3 t=-3
{3,-3}
the steps i was taught were
get zero on one side of equation
factor completely
set each to zero
solve
but I am stuck on these problems I can get them all set to zero and then that's it, i'm stuck after that
^2 = squared ^3 = cubed ^4=to the 4th power
1) t^3-t=0
2)3u^2+7u-6=0
3)x^2-6x-72=0
4)(s-1)^2(s-3)^2
5)0.2x^2-1.1x+0.5=0
6) (x^2-3)^2+(x^2-3)-2=0
7) (x^2-3x+2)^3=0
8) f(x)=(x+1)^4 +4(x+1)^3
If anyone could help me that would be amazing!!!!!!! I need help a.s.a.p!!!!
Hello, mathallychallenged!
The steps i was taught were:
. . get zero on one side of equation
. . factor completely
. . set each to zero
. . solve . . . . . . . . Correct!
In some of these, the factoring may be tricky.
Factor: .
Then we have: .
Factor: .
Then we have: .
Factor: . . . . etc.
This is not an equation.
I assume it's supposed to be: .
It is already factored, right?
So we have: .
Multiply by 10: .
Factor: . . . . etc.
Replace with .
The equation becomes: .
. . which factors: .
. . and we get: .
Since
. . we have: .
It is already factored.
Take the cube root of both sides: .
Factor: . . . . etc.
. Find the zeros.
We have: .
Factor: .
And we have: .