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  1. #1
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    help

    If a_1 = 2 and a_{n+1} = (a_n - 1)^2, then find the value of a_{17} ?


    i got answer zero is it correct !
    Last edited by mr fantastic; August 15th 2009 at 01:41 AM. Reason: Corrected the equation using latex
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  2. #2
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    Quote Originally Posted by bluffmaster.roy.007 View Post
    If a1 = 2 and an+1=(an - 1)2, then find the value of a17?


    i got answer zero is it correct !
    If you show your working it will be easier to review your answer.
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  3. #3
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    a1+1=a2=(2-1)^2 =1
    a2+1=a3=(1-1)^2=0
    so i thought it had a pattern and i think a17 must also be zero is my approach correct
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  4. #4
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    Quote Originally Posted by bluffmaster.roy.007 View Post
    If a_1 = 2 and a_{n+1} = (a_n - 1)^2, then find the value of a_{17} ?


    i got answer zero is it correct !
    Yes (now that it's clear that the 2 in the expression was an exponent and not a multiplier).
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