My teacher said this is incorrect because I should be taking the natural log of both sides of the equation. How would I do that?

y = e^3

y = e^3

e = 3SQRT(y)

e = y^1/3

e^2 = y^2/3

Thanks

2. what are you trying to find? if you are looking for y, you have it already. e^3 is a constant.

3. Originally Posted by bobbyboy1111
My teacher said this is incorrect because I should be taking the natural log of both sides of the equation. How would I do that?

y = e^3

y = e^3

e = 3SQRT(y)

e = y^1/3

e^2 = y^2/3

Thanks

remember that when you have y = b ^ x, this can be written as log_b y = x.

In this case, b = e, so log_e (y) = 3. Log to base e is written ln, so this becomes ln (y) = 3.

But, it's not clear to me what problem you are really trying to solve. Are you trying to solve for y? If so, just compute e^3 on your calculator, and that's the answer.

4. Originally Posted by QM deFuturo
remember that when you have y = b ^ x, this can be written as log_b y = x.

In this case, b = e, so log_e (y) = 3. Log to base e is written ln, so this becomes ln (y) = 3.

But, it's not clear to me what problem you are really trying to solve. Are you trying to solve for y? If so, just compute e^3 on your calculator, and that's the answer.
My teacher told me to solve by taking the natural log of both sides of the equation, that's it, finito.

So, would this be correct?:

y = e^3
log_e(y) = 3
ln(y) = 3

Can this be simplified any further?

Thanks.

5. no. natural log of e^3 is 3 (obviously)
natural log of y is lny (obviously)
there is nothing more to it in this case.

6. Originally Posted by furor celtica
no. natural log of e^3 is 3 (obviously)
natural log of y is lny (obviously)
there is nothing more to it in this case.
So would that be:

y = e^3

ln(y) = 3?

7. Originally Posted by bobbyboy1111
My teacher said this is incorrect because I should be taking the natural log of both sides of the equation. How would I do that?

y = e^3

y = e^3

e = 3SQRT(y)

e = y^1/3

e^2 = y^2/3

Thanks
$\displaystyle y=e^3$

$\displaystyle \log _e y = \log _e (e^3)$ note that $\displaystyle log_e = ln$

$\displaystyle \ln y = 3 \ln (e)$

$\displaystyle \ln y = 3$

8. Originally Posted by bobbyboy1111
My teacher said this is incorrect because I should be taking the natural log of both sides of the equation. How would I do that?

y = e^3

y = e^3

e = 3SQRT(y)

e = y^1/3

e^2 = y^2/3

Thanks
Posted and discussed here: http://www.mathhelpforum.com/math-he...n-correct.html