# Thread: Is this equation correct?

1. ## Is this equation correct?

y = e^3

e^3 = y
e = 3SQRT(y)
(3SQRT(y))^2 = e^2
3^2y = e^2
9y = e^2
y = e^2/9

Thanks

2. Originally Posted by bobbyboy1111
y = e^3

e^3 = y
e = 3SQRT(y)
(3SQRT(y))^2 = e^2
3^2y = e^2
9y = e^2
y = e^2/9

Thanks
No, it fails at the first line.

e=cbrt(y)

CB

3. Originally Posted by bobbyboy1111
y = e^3

e^3 = y
e = 3SQRT(y)
(3SQRT(y))^2 = e^2
3^2y = e^2
9y = e^2
y = e^2/9

Thanks
I do not know exactly what you want but I think this is what you want

$\displaystyle e^3=y$

$\displaystyle e=\sqrt[3]{y}$

$\displaystyle e=y^{\frac{1}{3}}$

$\displaystyle e^2=y^{\frac{2}{3}}$

4. Originally Posted by bobbyboy1111
y = e^3
What were the instructions? What are you supposed to do with the above equation?

Thank you!

5. Originally Posted by stapel
What were the instructions? What are you supposed to do with the above equation?

Thank you!
Solve.

6. Solve y = e^3 ???

7. Originally Posted by songoku
Solve y = e^3 ???
Exactly. I'm telling you, I have some weird math problems.

8. Hi bobbyboy1111

That's sure one super weird problem. How can you solve y = e^3 ?

IMO, y= e^3 itself can be considered as solution...

9. Originally Posted by songoku
Hi bobbyboy1111

That's sure one super weird problem. How can you solve y = e^3 ?

IMO, y= e^3 itself can be considered as solution...

Does the post I originally wrote make sense? If so, I would try that and see what happens

10. Originally Posted by bobbyboy1111
Solve.
Originally Posted by songoku
Solve y = e^3 ???
$\displaystyle e^3 \approx 20.086$

11. Originally Posted by bobbyboy1111
Does the post I originally wrote make sense? If so, I would try that and see what happens
No, it doesn't. You can take a look post #3 by Amer as reference

And do not use that kind of color since it's hard to read