“b” varies inversely as the square root of “c”. If b = 1 when c = 16, find b when c = 6.

b = k/x

1= k/SQRT(16)

k/SQRT(16) = 1

k/SQRT(16) * SQRT(16) = 1 * SQRT(16)

k = 1 * SQRT(16)

k = 4

Now that I have the variation constant, I can plug in the x-value they gave me, and find the value of y:

y = 4/6

y = 2/3