Hi everyone

I need help for this problem :

If $\displaystyle 2*\log_2 (x-2y)=\log_3 (xy)$ , find $\displaystyle \frac{x}{y}$

$\displaystyle 2*\log_2 (x-2y)=\log_3 (xy)$

$\displaystyle \log_2 (x-2y)^2=\log_3 (xy)$

How to deal with different base?

Thx