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Math Help - Solving systems

  1. #1
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    Solving systems

    Hey everyone I am having a problem with something. We were learning about systems and substitution equations and how to solve them today and I am not really understanding where they are going with this. I am given the two equations but I am not sure what I am supposed to do from there? There were a few other equations on here that I was able to do but these ones are formatted different so can you please help explain these to me if possible? Thank you.

    X + 3Y = 6
    4X - 2Y = 10


    and

    5X + Y = 11
    10X + 2Y = 20


    I was looking at some other threads in here but everything seems so confusing; these two were formatted differently from the ones I read. Any help is appreciate, thanks.
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  2. #2
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    Quote Originally Posted by JH2Xtreme View Post

    X + 3Y = 6
    4X - 2Y = 10
    X + 3Y = 6 lets call this eqn 1

    4X - 2Y = 10 lets call this eqn 2

    Doing some work on equation 1: X + 3Y = 6 \Rightarrow X = 6- 3Y so now we can sub  6- 3Y into equation 2 where we see X

    equation 2: 4X - 2Y = 10 becomes 4(6-3Y) - 2Y = 10 can you solve for Y now?
    Last edited by pickslides; August 12th 2009 at 07:45 PM. Reason: typo
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