# Solving systems

• Aug 12th 2009, 07:33 PM
JH2Xtreme
Solving systems
Hey everyone I am having a problem with something. We were learning about systems and substitution equations and how to solve them today and I am not really understanding where they are going with this. I am given the two equations but I am not sure what I am supposed to do from there? There were a few other equations on here that I was able to do but these ones are formatted different so can you please help explain these to me if possible? Thank you.

X + 3Y = 6
4X - 2Y = 10

and

5X + Y = 11
10X + 2Y = 20

I was looking at some other threads in here but everything seems so confusing; these two were formatted differently from the ones I read. Any help is appreciate, thanks.
• Aug 12th 2009, 07:43 PM
pickslides
Quote:

Originally Posted by JH2Xtreme

X + 3Y = 6
4X - 2Y = 10

\$\displaystyle X + 3Y = 6\$ lets call this eqn 1

\$\displaystyle 4X - 2Y = 10\$ lets call this eqn 2

Doing some work on equation 1: \$\displaystyle X + 3Y = 6 \Rightarrow X = 6- 3Y \$ so now we can sub \$\displaystyle 6- 3Y \$ into equation 2 where we see X

equation 2: \$\displaystyle 4X - 2Y = 10\$ becomes \$\displaystyle 4(6-3Y) - 2Y = 10\$ can you solve for Y now?