If y = -x^2 + 3, what is the largest possible value of y?
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I assume that it would be y=3 that you get when you put x=0. For the other values of x because it's negative you will start getting negative y, therefore i believe y=3 is the biggest value.
Originally Posted by sharkman If y = -x^2 + 3, what is the largest possible value of y? The function $\displaystyle y = -x^2 + 3$ is simply $\displaystyle y = x^2$ tipped upside down then moved up 3 places.
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