I do not understand what you posted.
Could you ask someone to help you with your English?
1. A person gets $20,000
2. This person then spends an amount of money
3. 40% of the remainder attracts 6% interest
4. 10% of the remainder (from step 2) attracts 10% interest.
Let x be the amount he spends and y be the amount which gets interest
40% of y gets 6% interest:
60% of y gets 10% interest:
0.4y(1.06)^n + 0.6y(1.10)^n = 1250
If we assume n is over one period of time (usually annually) so that will cancel
I interpreted it differently . . .
A person spends a part of amount of $20,000 for buying.
40% of the remaining amount is given at 6% interest
and the rest of the money is given at 10% interest.
If the total interest the person gets is $1250,
then what is the amount he used for buying?
The person has $20,000.
He spend dollars for buying.
He has dollars remaining.
40% of this remainder is: . dollars.
This earns 6% interest: .
60% of the remainder is: . dollars.
This earns 10% interest: .
The total interest is $1250: .
We have: .
Therefore, he used $5,119.05 for buying.
Mr sorobon is rite..........
lets see how eazy it is..........consider x be the amount remainin...
that is x=20,000-amount used for buying.
40% of remaining amount x gets 6%interest
and for second interest (0.6)(0.1)(x)
together they make 1250$=0.024x+0.06x
so amount used for buying is 20,000-x
and that is 5119.9$....