Thanks will be given to those who help. I am in dire need of it too, for some problems. Here is my work:

1.Find the discriminant

-10x^2 - 6x + 5 = 0

-(-6)^2 -4(-10)(5)
(36 + 200)
236

236 is the discriminant.

2. Find the discriminant

2x^2 + 6x + 1 = 0

(6)^2- 4(2)(1)
(36 - 8)
28

28 is the discriminant

3. Could someone continue this and show me the complex solution, I
cannot calculate it and have been struggling with the complex number part for a long time. Here is what I have so far:

2x^2 - 5x + 4 = 0

x = -(-5)+_ SQRT((-5)^2 -4(2)(4))/2(2)
= 5 +_ SQRT(25 - 32)/4 = 5 +_SQRT(-7)/4

4. Could someone please show me how to solve these two (#4/#5)?

4x^2 - 5x - 6 <= 0

5. 2x^2 + 9x + 4 < 0

6. x^2 + 3x - 10 = 0 This one was solved using the quadratic formula, but I need to find the pair of numbers for: The product of two numbers is 10. One number is 3 more than the other number. What is the quadratic equation that models these numbers? How would I do this?

x = -(3) +_ SQRT((3)^2) - 4(1)(-10)/2(1)
= -3 +_ SQRT(9 + 40)/2 = -3 +_ SQRT(49)/ 2
= -3 +_7/2 = -3 - 7/2, -3 + 7/2
= -10/2, 4/2 = -5, 2
x = -5, x = 2

Thanks!

2. Hi bobbyboy1111

1. correct
2. correct

3. $\frac{5\pm\sqrt{-7}}{4}=\frac{5\pm i\sqrt{7}}{4}$

Note that : $i=\sqrt{-1}$

4 and 5. You can start by factorizing them and find the critical values

6. Another way to solve x^2 + 3x - 10 = 0 :

$x^2 + 3x - 10 = 0$

$(x+5) (x-2)=0$

$x=-5 , x = 2$

Then, you need to find the pair of numbers for: The product of two numbers is 10. One number is 3 more than the other number.

Let : the numbers are a and b

*The product of two numbers is 10 -----------------------> ab = 10 ..........(1)
*One number is 3 more than the other number --------> a = b + 3 ........(2)

Substitute the two equations. ^^

EDIT : I think it's better for you to start learning latex : http://www.mathhelpforum.com/math-he...-tutorial.html