3y+4= y/2+9
how do i do this?! im confused :(
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3y+4= y/2+9
how do i do this?! im confused :(
Get the "unknown" (in this case y) by itself on one side of the equation. Here, you might start by getting both "y"s on the left and anything not involving "y" on the right. Since there is a "y/2" added on the left, do the opposite: subtract y/2 from both sides: 3y+ 4- y/2= y/2+ 9- y/2 becomes (3- 1/2)y+ 4= 9 or (6/2- 1/2)y+ 4= (5/2)y+ 4= 9. Now subtract 4 from both sides: (5/2)y+ 4- 4= 9- 4 or (5/2)y= 5. Since y is now multiplied by 5/2, do the opposite: divide both sides by 5/2 (or, same thing, multiply both sides by 2/5): (2/5)(5/2)y= (2/5)(5) or y= 2.Quote:
Originally Posted by brainfreeze
thanks, but im stuck again lol,
3/4t= -1 7/8
ive tried to move 7/8 to the other side,
but only to fail.
this is what keeps happening
3/4t= -1 7/8
(3/4÷7/8)t = -1
my answer keeps coming up t=-1 1/6
but the answer is -2 1/6
now i know ive done something wrong
but im not sure what it is lol
Is this the problem you want to solve?
thats exactly what im trying to solve
Quote:
Originally Posted by SENTINEL4
@OP: Start by multiplying both sides of the equation by 8:Quote:
Originally Posted by brainfreeze
6t = -7.
Therefore t = -7/6. Your answer is correct.