Would I set both of them equal to 0 and solve using the quadratic formula? Those that help me will be thanked!
Solve each inequality:
1. 4x^2 - 5x - 6 <= 0
2. 2x^2 + 9x + 4 < 0
Solving Quadratic Inequalities: Examples
Hope this helps
LHS = Left Hand Side
You need to decompose the polynomials on the LHS into a product of factors which when multiplied give the original form.
It should be clear that $\displaystyle (x-2)(4x-3) = 0$ for $\displaystyle x=2$ and $\displaystyle x = -\frac{3}{4}$. It can easily be checked that for values between -3/4 and 2 it is negative.
See also http://www.wolframalpha.com/input/?i=4+x^2+-+5+x+-+6+<%3D+0
The examples, like "x2 + 2x – 8 < 0" and "–x2 + 6x – 9 > 0" are quadratic, they have "zero" on the other side of the inequality, and they involve factoring, just as you've been advised to proceed here. How are those examples "truly" different from what you are doing?