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- Aug 8th 2009, 10:45 AM #1

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## help with ln and log

I have been trying to solve it for a few days for my nephew but I am not able to remember what I learned back in school 15 years ago, please any help is appreciated

ln(2x-1) + (ln(2x-1)^2 = 4

And also, can you please confirm if the following one is correct?

log(x^2 - 9x) - logx = 2

log (x^2-9x / x) = 2

log (x-9) = 2

x-9 = 100

x = 109

Thank you in advanced!

- Aug 8th 2009, 10:51 AM #2

- Aug 8th 2009, 10:55 AM #3

- Aug 8th 2009, 11:15 AM #4

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- Aug 8th 2009, 11:55 AM #5
Well yes, it makes all the difference! Now I think that the interpretation used by

**earboth**is much more plausible. I say "more plausible": the situation is not entirely clear (to me at least). I believe that certain rules, especially as regards the dropping of parentheses meant to enclose the function argument, are used differently by different people. (And everyone believes that the rules he or she uses are The Right Ones.)

Here, if squaring of the value of the second were intended, one would (hopefully) write instead of . And since this is not the case, I assume that squaring is meant to take place*before*the second gets applied.