# Thread: A tricky question on %'s....

1. ## A tricky question on %'s....

A shopkeeper defrauds both the dealer and the customer by measuring weights incorrectly.When he is purchasing items from the dealer,he takes 20% more than the indicated weights and when he is selling them to the customer,he gives 20% less than the indicated weight.if the price,that the shopkeeper charges his customer is the same as what the dealer charges the shopkeeper,then what profit percentage does the shopkeeper make?

2. Originally Posted by player007
A shopkeeper defrauds both the dealer and the customer by measuring weights incorrectly.When he is purchasing items from the dealer,he takes 20% more than the indicated weights and when he is selling them to the customer,he gives 20% less than the indicated weight.if the price,that the shopkeeper charges his customer is the same as what the dealer charges the shopkeeper,then what profit percentage does the shopkeeper make?
Lets say that dealer is selling at the rate of 100 per kg.
Since the shopkeeper measures 20% more...he buys at 100 per 1.2 kg(he paid 100 per kg but got 100 per 1.2kg )
Hence the shopkeeper bought at 100 per 1.2 kg or 83.33 per kg.

Now shopkeeper sells at 100 per .8 kg(frauds by 20%)
100 per .8kg is 125 per kg

hence, per kg shopkeeper has profit of 125-83.33=41.66

Profit percentage= $\frac{41.66}{83.33}\cdot 100$% $=50$%

3. That was a nice solution u gave.....it's perfect.

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# A shopkeeper defrauds both the dealer and the customer by measuring the weights incorrectly. When he is purchasing items from the dealer, he takes 20% more than the indicated weight and while selling he gives to the customer a quantity, such that if 20% i

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