Help with surds?

**Dranalion** · August 7th 2009, 04:47 PM

Hello,

Not too sure if this is the correct forum to put this thread into, but I am trying to figure out:

(- sqrt2 / 3)^2 = 2/9?

Sorry, its seems basic, but I can't get my head around it?!

Any help is much appreciated!

*sqrt is square root!

Thanks!

**mathaddict** · August 7th 2009, 05:21 PM

Originally Posted by Dranalion

Hello,

Not too sure if this is the correct forum to put this thread into, but I am trying to figure out:

(- sqrt2 / 3)^2 = 2/9?

Sorry, its seems basic, but I can't get my head around it?!

Any help is much appreciated!

*sqrt is square root!

Thanks!

$<br /> (-\sqrt{\frac{2}{3}})^2=-\sqrt{\frac{2}{3}}\times(-\sqrt{\frac{2}{3}})<br />$

$=\frac{2}{3}\times\frac{2}{3}$

$<br /> =\frac{2}{9}<br />$

**Dranalion** · August 7th 2009, 05:48 PM

Sorry, not too sure if it makes a difference or not, but only the 2 on the top is being square rooted?

As in:

(- sqrt2 / 3)^2

**Wilmer** · August 7th 2009, 06:19 PM

Originally Posted by Dranalion

Sorry, not too sure if it makes a difference or not, but only the 2 on the top is being square rootedAs in:
(- sqrt2 / 3)^2

(-1)^2 = -1 * -1 = 1 ; right?

So (-1sqrt(2))^2 = (sqrt(2))^2 ; right?

(sqrt(2))^2 = 2 ; 3^2 = 9 : so 2/9 ; kapish?

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