1. ## Help with surds?

Hello,

Not too sure if this is the correct forum to put this thread into, but I am trying to figure out:

(- sqrt2 / 3)^2 = 2/9?

Sorry, its seems basic, but I can't get my head around it?!

Any help is much appreciated!

*sqrt is square root!

Thanks!

2. Originally Posted by Dranalion
Hello,

Not too sure if this is the correct forum to put this thread into, but I am trying to figure out:

(- sqrt2 / 3)^2 = 2/9?

Sorry, its seems basic, but I can't get my head around it?!

Any help is much appreciated!

*sqrt is square root!

Thanks!
$
(-\sqrt{\frac{2}{3}})^2=-\sqrt{\frac{2}{3}}\times(-\sqrt{\frac{2}{3}})
$

$=\frac{2}{3}\times\frac{2}{3}$

$
=\frac{2}{9}
$

3. Sorry, not too sure if it makes a difference or not, but only the 2 on the top is being square rooted?

As in:

(- sqrt2 / 3)^2

4. Originally Posted by Dranalion
Sorry, not too sure if it makes a difference or not, but only the 2 on the top is being square rootedAs in:
(- sqrt2 / 3)^2
(-1)^2 = -1 * -1 = 1 ; right?

So (-1sqrt(2))^2 = (sqrt(2))^2 ; right?

(sqrt(2))^2 = 2 ; 3^2 = 9 : so 2/9 ; kapish?