I can barely simplify regular fractions! My book's explanation of how to do this has me so terribly confused...
$\displaystyle \frac{\frac{b}{b+9}+\frac{7}{5b}}{\frac{b}{3b+27}+ \frac{4}{b}}$
Thanks for any help you can offer.
I can barely simplify regular fractions! My book's explanation of how to do this has me so terribly confused...
$\displaystyle \frac{\frac{b}{b+9}+\frac{7}{5b}}{\frac{b}{3b+27}+ \frac{4}{b}}$
Thanks for any help you can offer.
Expanding a bit on the previous (and spot-on!) reply, multiply the fraction, top and bottom, by the LCM of the four sub-fractions:
$\displaystyle \frac{\displaystyle\frac{15b(b\, +\, 9)}{1}\left(\frac{b}{b\, +\, 9}\right)\, +\, \frac{15b(b\, +\, 9)}{1}\left(\frac{7}{5b}\right)}{\displaystyle\fra c{15b(b\, +\, 9)}{1}\left(\frac{b}{3(b\, +\, 9)}\right)\, +\, \frac{15b(b\, +\, 9)}{1}\left(\frac{4}{b}\right)}$
Cancel stuff to get:
$\displaystyle \frac{15b(b)\, +\, 3(b\, +\, 9)(7)}{5b(b)\, +\, 15(b\, +\, 9)(4)}$
I'll bet you can see where to go from there!
Now that I've finished my lunch...
$\displaystyle \frac{3(5b^2\, +\, 7b\, +\, 63)}{5(b^2\, +\, 12b\, +\, 108)}$
Should I leave it like this? Based on the answers of similar problems in the book, I think I should distribute it out to...
$\displaystyle \frac{15b^2\, +\, 21b\, +\, 189)}{5b^2\, +\, 60b\, +\, 540)}$
How's this look?
Much appreciate the help guys.