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Math Help - ambigous

  1. #1
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    11. If -1 < y < 0, then which of the following is true
    A. y <
    B. y
    C.
    & so on……

    for pentagon the diagonals are 4 what is it for heptagon
    Last edited by mr fantastic; August 6th 2009 at 05:17 AM. Reason: Merged posts
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  2. #2
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    For your first post.Note;

    if 0<|y|<1

    then |y^n|<|y^m| and n>m

    if -1<y<0

    then |y^3|<|y^2| and y^3<y^2 regardless of sign

    |y^4|<|y^2| and y^4<y^2 regardless of sign

    y,y^3 are -ve, y^2,y^4 are positive

    so y<y^3<y^4<y^2

    You could just plug in y=-0.5 and it will tell you which is bigger
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  3. #3
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    Quote Originally Posted by bluffmaster.roy.007 View Post
    for pentagon the diagonals are 4 what is it for heptagon
    Draw the shape and draw all the diagonals. Now count them.

    Quote Originally Posted by bluffmaster.roy.007 View Post
    11. If -1 < y < 0, then which of the following is true
    A. y <
    B. y
    C.
    & so on……
    Choose a convenient value of y and test each statement.
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