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Math Help - Sat II math help

  1. #1
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    Sat II math help

    √(10)√(2)/
    √(15) =?


    If a ≠ -b, then a-b/a+b =?


    what is the reciprocal of a/b+b/a?


    x/yz divided by (y) =?

    thanks!

    Please show steps if possible
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  2. #2
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    Quote Originally Posted by original501 View Post
    √(10)√(2)/
    √(15) =?


    If a ≠ -b, then a-b/a+b =?


    what is the reciprocal of a/b+b/a?


    x/yz divided by (y) =?

    thanks!

    Please show steps if possible
    1. Note and use the following rules

    \sqrt{a} \sqrt{b} = \sqrt{ab}
    \sqrt{a^2b} = a \sqrt{b}

    2. This cannot be simplified further. a does not equal b because if it did there would be division by 0

    3. The reciprocal of x is 1/x. In other words flip the fraction.

    You could say \frac{1}{\frac{a}{b}+\frac{b}{a}} but that's crude and it would be better to get a single denominator first

    4. When dividing by a whole number/variable multiply the denominator by the value:

    <br />
\frac{1}{a} \div b = \frac{1}{ab}
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