Student this limit :
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$\displaystyle \lim_{x\to+\infty}\frac{sin x}{x}=0$ As $\displaystyle x\rightarrow+\infty$, sin x takes a finite value between 1 and -1. However, the denominator becomes infinitely large. So the limit is zero.
Originally Posted by alexmahone $\displaystyle lim x\rightarrow +\infty \frac{sin x}{x}$ I'can understing any thing !!!!
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Originally Posted by dhiab I'can understing any thing !!!! $\displaystyle \left| {\frac{{\sin (x)}} {x} - 0} \right| = \left| {\frac{{\sin (x)}} {x}} \right| \leqslant \left| {\frac{1} {x}} \right| \to 0\text{ as }x \to \infty $
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