# Student this limit

• August 5th 2009, 08:28 AM
dhiab
Student this limit
• August 5th 2009, 08:38 AM
alexmahone
$\lim_{x\to+\infty}\frac{sin x}{x}=0$

As $x\rightarrow+\infty$, sin x takes a finite value between 1 and -1. However, the denominator becomes infinitely large. So the limit is zero.
• August 5th 2009, 08:43 AM
dhiab
Quote:

Originally Posted by alexmahone
$lim x\rightarrow +\infty \frac{sin x}{x}$

I'can understing any thing !!!!
• August 5th 2009, 08:59 AM
stapel
Which part of the explanation and answer did you not understand?

Please be specific. Thank you! (Wink)
• August 5th 2009, 09:02 AM
Plato
Quote:

Originally Posted by dhiab
I'can understing any thing !!!!

$\left| {\frac{{\sin (x)}}
{x} - 0} \right| = \left| {\frac{{\sin (x)}}
{x}} \right| \leqslant \left| {\frac{1}
{x}} \right| \to 0\text{ as }x \to \infty$