Student this limit : http://www.mathramz.com/xyz/latexren...bb063793a2.png

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- Aug 5th 2009, 08:28 AMdhiabStudent this limit
**Student this limit : http://www.mathramz.com/xyz/latexren...bb063793a2.png** - Aug 5th 2009, 08:38 AMalexmahone
$\displaystyle \lim_{x\to+\infty}\frac{sin x}{x}=0$

As $\displaystyle x\rightarrow+\infty$, sin x takes a finite value between 1 and -1. However, the denominator becomes infinitely large. So the limit is zero. - Aug 5th 2009, 08:43 AMdhiab
- Aug 5th 2009, 08:59 AMstapel
Which part of the explanation and answer did you not understand?

Please be specific. Thank you! (Wink) - Aug 5th 2009, 09:02 AMPlato