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Math Help - Need help with Easy (but not for me) pronumerals!

  1. #1
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    Need help with Easy (but not for me) pronumerals!

    Hey guys, I'm not that good at maths especially pro numerals and my teacher is terrible, so I need your help.

    I would greatly appreciate the answers and the working out for these problems. What does the x equal?! D:

    5x-6=3x-9


    6-3x=4


    2(x+3)=5-x


    3(x+4)-2x-8=5


    4-5x
    ---- = 4
    7


    3(2x-3)
    -------= 5
    4

    And the ----- are dividing lines... Thanks!
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  2. #2
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     5x-6=3x-9

    eliminate x on one side by -3x gives

     2x-6=-9

    add 6 to both sides to leave the unknown by itself on the LHS

     2x=-3

    divde both sides by 2 to get

     x=\frac{-3}{2}

    do you know your inverse operations?
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  3. #3
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    Yeah, a little but barely.
    My maths teacher is supposed to be a science teacher, so she's terrible with these kinda things.
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  4. #4
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     2(x+3)=5-x

    You should expand the brackets with this type of problem

     2x+6=5-x

    now follow similar steps to what I posted above.
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  5. #5
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    when you take off the x from the RHS, does the 2x become 2 or 1x? Or dosn't it change?
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  6. #6
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    Do another step by step please?
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  7. #7
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    2x+6=5-x
    => 2x + x = 5-6
    => 3x=-1
    => x=-1/3

    4-5x
    ---- = 4
    7

    => 4-5x = 28
    => -5x = 24
    => x= -24/5

    etc
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  8. #8
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    Quote Originally Posted by Fame View Post
    when you take off the x from the RHS, does the 2x become 2 or 1x? Or dosn't it change?
    2x+6=5-x

    add 1x to both sides

    2x(+x)+6=5-x(+x)

    3x+6=5

    now take 6 from both sides

    3x=-1

    divide 3 from both sides

    x=\frac{-1}{3}
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