# Thread: need help putting into words

1. ## need help putting into words

I need to show which of the two expressions is larger and explian why. I know which is the larger number,but can not put it into words to explain. Anyone have any ideas?

a) (1/2)'2 or (1/3)'3

b)(1/3)'-2 or (1/3)'-3

*Note: (1/2)'2 is "one half squared"*

2. Originally Posted by math619
I need to show which of the two expressions is larger and explian why. I know which is the larger number,but can not put it into words to explain. Anyone have any ideas?

a) (1/2)'2 or (1/3)'3

b)(1/3)'-2 or (1/3)'-3

*Note: (1/2)'2 is "one half squared"*
$\displaystyle (1/2)^2=1/4$
$\displaystyle (1/3)^2=1/9$

Now, what is larger?
Taking something and dividing it into 4 parts of equal length, or taking something dividing it into 9 parts of equal length?
Surly the first one.
Thus,
$\displaystyle 1/4>1/9$

3. Originally Posted by math619
I need to show which of the two expressions is larger and explian why. I know which is the larger number,but can not put it into words to explain. Anyone have any ideas?

a) (1/2)'2 or (1/3)'3

b)(1/3)'-2 or (1/3)'-3

*Note: (1/2)'2 is "one half squared"*
(1/2)^2=1/4=9/36
(1/3)^2=1/9=4/36
Now you can compare, 9/36>4/36, 1/4>1/9.

4. Originally Posted by math619
I need to show which of the two expressions is larger and explian why. ...

b)(1/3)'-2 or (1/3)'-3
Hello,

with negative exponents you have to use the following property:

$\displaystyle a^{-n}=\frac{1}{a^n}$

$\displaystyle \left(\frac{1}{3} \right)^{-2}=\frac{1}{\left(\frac{1}{3} \right)^2}=\frac{1}{\frac{1}{9}}=9$

$\displaystyle \left(\frac{1}{3} \right)^{-3}=\frac{1}{\left(\frac{1}{3} \right)^3}=\frac{1}{\frac{1}{27}}=27$

Now you can compare!

EB