Find the number of points (x, y), where x and y are non-negative integers, such that $\displaystyle 2x-4\le y \le -3x+40-3y$ Anyone can help?
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Sorry! Wrong
Last edited by DeMath; Aug 4th 2009 at 02:47 AM.
I subs. (0,10) and the inequality is still right.... Strangely, I got infinite numbers of solution... EDIT : Ups, not infinite. My rough sketch of the graphs was wrong ^^
Last edited by songoku; Aug 4th 2009 at 12:37 AM.
ya..songoku is right, (0, 10) is a possible solution. I can solve it graphically, i draw the lines y=2x-4 and 4y=-30x+40 and find the region satisfying the inequalities. I got 39 points. any other ways to do this?
Sorry, I understood your task not correct.
Last edited by DeMath; Aug 4th 2009 at 02:50 AM. Reason: wrong
Hi DeMath Have you tried (0,10) ? ^^
i think you are wrong demath if your answer is correct, then (5, 0) is a possible solution, But it doesn't satisfy the inequalities...
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