One method is substitution. You take one equation and solve for one of the variables. I picked the second problem because the second equation is already solved for one of the variables (y). You plug this into the 1st equation for y like this:

-2x + y = 8

-2x + (-3x - 2) = 8

-5x - 2 = 8

-5x = 10

x = -2

Then you take this result and plug it into the 2nd equation:

y = -3x - 2

y = -3(-2) - 2

y = 6 - 2

y = 4

01

EDIT: too early in the morning...