I don't understand this problem:
solve the following system for (x;y):
log x base of 9 + log 8 base of y = 2
log 9 base of x + log y base of 8 = 8/3
Hello, lrn24gve!
My solution is not an improvement on the others . . .
Solve the following system for
. .
Theorem: .
The equations become:
. .
Hence: .
Subsitute into (1): .
. . which simplifies to: .
. . which factors: .
And we have two equations to solve:
. .
. . . . Substitute into (3): .
. . . . . . Then: .
. .
. . . . Substitute into (3): .
. . . . . . Then: .
Solutions: .