I don't understand this problem:

solve the following system for (x;y):

log x base of 9 + log 8 base of y = 2

log 9 base of x + log y base of 8 = 8/3

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- Jan 7th 2007, 07:05 PMlrn24gvelogarithms
I don't understand this problem:

solve the following system for (x;y):

log x base of 9 + log 8 base of y = 2

log 9 base of x + log y base of 8 = 8/3 - Jan 7th 2007, 07:41 PMThePerfectHacker
- Jan 7th 2007, 08:23 PMCaptainBlack
- Jan 8th 2007, 10:57 AMSoroban
Hello, lrn24gve!

My solution is not an improvement on the others . . .

Quote:

Solve the following system for

. .

Theorem: .

The equations become:

. .

Hence: .

Subsitute into**(1)**: .

. . which simplifies to: .

. . which factors: .

And we have two equations to solve:

. .

. . . . Substitute into**(3)**: .

. . . . . . Then: .

. .

. . . . Substitute into**(3)**: .

. . . . . . Then: .

Solutions: .