I've banged my head senseless on an exponential equation lately. I can't seem to solve however i try. Any help would be appreciated.
problem:
4^2x - 4^x = 8 * 4^(x+3)
solve for x
Lets assume the equation is:
$\displaystyle 4^{2x}-4^x=8 \times 4^{x+3}$
or:
$\displaystyle 4^{2x}-4^x=8 \times 4^3 \times 4^{x}$
rearrange:
$\displaystyle (4^{x})^2-513\times 4^x=4^x(4^x-513)=0$
so either $\displaystyle 4^x=0$ which is impossible or:
$\displaystyle
4^x=513
$
and you should be able to finish this yourself from that.
CB