the cubic polynomial f(x) is such that the coefficient of x^3 is 1 and the roots of f(x)=0 are 1, k , k^2 . it is given that f(x) has a remainder of 7 when divided by x-2.

show that k^3 - 2k^2 - 2k - 3 =0.

thanks teach me how to solve. thank you very much