I don't know how to write the symbol sigma on here but the lower limit is 1 and the upper limit is 4 and (xi - yi)^2. I need the method on how to do it.
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I don't know how to write the symbol sigma on here but the lower limit is 1 and the upper limit is 4 and (xi - yi)^2. I need the method on how to do it.
First of all, we need to be clear on what the problem is. Do you mean:Quote:
Originally Posted by marie7
?
yes that's correct sorry I don't know how to do the symbols
OK... well this is sort of an odd sum. TheQuote:
Originally Posted by marie7
and
aren't involved in the indexing, so we can take them out. We get
Now the sum should be very simple to solve.
Well the x and y have number values and I just wanted the method so I could do it myself but here are the numbers:Quote:
Originally Posted by AlephZeroOK... well this is sort of an odd sum. The
Now the sum should be very simple to solve.
for x1 = 2, x2 = -3, x3 = 10 x4 = -5, x5 = -3
for y1 = -1, y2 = 3, y3 = 5, y4 = 7, y5 = -2.
i is supposed to represent for example 1 in x1, 2 in x2 etc. Its a little i.
Alright, so when I asked you previously if I had typed up the problem correctly, and you said "yes," that wasn't true, evidently. And you are now providing, in addition, a hugely crucial portion of the problem that you also neglected to mention.Quote:
Originally Posted by marie7
So now I ask you again. Think very hard. Is this the problem:
?
yeah it is.
Well, then the easiest way to do it is just expand the sum, and substitute the values:
Simply plug in the values and do the arithmetic.
I got -146 as my answer, is that correct?
No, Marie. 'fraid not.
Hint:
Spoiler:
I plugged the numbers in like this (2 -(-1))^2 + (-3-3)^2 + (10 - 5)^2 + (-5-7)^2
Am I right?
Ah, no, I'm afraid not, for at least 3 reasons. First, I have done the arithmetic myself based on the numbers you provided, and reached a different solution. Second, your answer is a negative number, and since the expression at hand involves the sum of four squares, a negative answer is impossible. Thirdly, you have provided a question involving a finite sum with 4 terms, and supplied data for 5 terms, so something is bound to be wrong with just about any answer you come up with.Quote:
Originally Posted by marie7
yes but the upper limit is four so I only do from 1 to four not 1 to five, does that make sense?
You plugged 'em in right, but unfortunately arrived at the wrong answer. What did you do after that?Quote:
Originally Posted by marie7
Look at my last post for a hint.
Correct!Quote:
Originally Posted by marie7