any easy way to solve this problem
Note that the decimal places indicate powers of 10, in the divisors, so you can sort-of cancel out to get:
. . . . .$\displaystyle \frac{(122)(9312)(44)}{(233)(369)(211)}$
Then factorization gives:
. . . . .$\displaystyle \frac{(2\times 61)(32\times 3 \times 97)(4\times 11)}{(233)(9\times 41)(211)}$
The only thing that cancels is the 3 from on top with a factor of 3 from the 9 underneath. You're stuck multiplying out the rest, I'm afraid.